document.write( "Question 974083: s + s+t/s-t = 1/t + s+t/s-t , for t\r
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Algebra.Com's Answer #596098 by Alan3354(69443) $\"\"$ $\"About$

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s + s+t/s-t = 1/t + s+t/s-t , for t\r
\n" ); document.write( "\n" ); document.write( "Is this clear?
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\n" ); document.write( "Much better.
\n" ); document.write( "s + s+t/s-t = 1/t + s+t/s-t
\n" ); document.write( "The addition of parentheses eliminates ambiguities:
\n" ); document.write( " $\"s+%2B+s%2Bt%2Fs-t+=+1%2Ft+%2B+s%2Bt%2Fs-t\"$ As entered.
\n" ); document.write( " $\"s+%2B+%28s%2Bt%29%2F%28s-t%29+=+1%2Ft+%2B+%28s%2Bt%29%2F%28s-t%29\"$ Probably what you meant.
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\n" ); document.write( "Multiply thru by s-t
\n" ); document.write( "s(s-t) + s+t = (s-t)/t + s+t
\n" ); document.write( "Subtract (s+t)
\n" ); document.write( "s(s-t) = (s-t)/t
\n" ); document.write( "Divide by (s-t)
\n" ); document.write( "s = 1/t
\n" ); document.write( "t = 1/s
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\n" ); document.write( "There are restrictions: t <> 0, s <> 0 and t <> s, makes the denominator zero. \n" ); document.write( "

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