document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=973977>Question 973977</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bunson Burner has 3 liters of a 10% acid solution. How much pure acid must be added to produce a 50% acid solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #596000 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=596000\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Bunson Burner has 3 liters of a 10% acid solution. How much pure acid must be added to produce a 50% acid solution?<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "0.10*3 + 1*x = 0.50(3+x)<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "10*3 + 100x = 50*3 + 50x<BR>\n" );
document.write( "50x = 40*3<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "x = (4/5)*3 = 2.4 liters (amt. of pure acid needed)<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "------------------- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );