document.write( "Question 973872: The length of a rectangle is 3 m less than the diagonal and the width is 8 m less than the diagonal. If the area is 84 m2, how long is the diagonal? Round your answer to the nearest tenth. \n" ); document.write( "
Algebra.Com's Answer #595974 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangle is 3 m less than the diagonal and the width is 8 m less than the diagonal. If the area is 84 m2, how long is the diagonal? Round your answer to the nearest tenth. \n" ); document.write( "*** \n" ); document.write( "let x=length of diagonal \n" ); document.write( "x-3=length of rectangle \n" ); document.write( "x-8=width of rectangle \n" ); document.write( ".. \n" ); document.write( "length*width=area \n" ); document.write( "(x-3)(x-8)=84 \n" ); document.write( "x^2-11x+24=84 \n" ); document.write( "x^2-11x-60=0 \n" ); document.write( "(x-15)(x+4)=0 \n" ); document.write( "x=15 \n" ); document.write( "how long is the diagonal? 15 m \n" ); document.write( "numbers do not check: \n" ); document.write( "By the pythagorean theorem: \n" ); document.write( "length^2+width^2=diagonal^2 \n" ); document.write( "12^2+7^2≠15^2 \n" ); document.write( "144+49≠15^2 \n" ); document.write( "193≠225 \n" ); document.write( " |