document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=973910>Question 973910</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The integral of log3 (x^2) - log3 (x+6)= 1.  After solving this I find that x= -3 and x = 6, which is correct.  My question is whether or not -3 is a solution?\r<BR>\n" );
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document.write( "when testing the original question should it be:\r<BR>\n" );
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document.write( "A) log3 (-3^2) - log3 (-3 + 6) =1 in which case -3 is a solution, or  should it be \r<BR>\n" );
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document.write( "B) 2log3 (-3) - log3 (-3 +6) =1, in which case -3  is not a solution because the first term, log3 (-3), does not exist? Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #595954 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=595954\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have the correct solution.\r<BR>\n" );
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document.write( "(log(x^2))/(log(3))-(log(x+6))/(log(3)) = 1. Now I multiply both sides by log(3)<BR>\n" );
document.write( "log(x^2)-log(x+6) = log(3)etcetera. You've already done the problem so it saves me some writing. <BR>\n" );
document.write( "You factor the left and get:<BR>\n" );
document.write( "(x-6) (x+3)= 0<BR>\n" );
document.write( "x-6= 0 or x+3= 0<BR>\n" );
document.write( "x= 6 or x= -3 This is your solution<BR>\n" );
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