document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=973877>Question 973877</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find an equation of the line that satisfies the given conditions.through (1/2, -2/3); perpendicular to line 6x-12y=1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #595917 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=595917\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6x-12y=1<BR>\n" );
document.write( "-12y=1-6x<BR>\n" );
document.write( "divide by -12<BR>\n" );
document.write( "y=(1/2)x - (1/12)<BR>\n" );
document.write( "Slope is 1/2<BR>\n" );
document.write( "Perpendicular slope is -2\r<BR>\n" );
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document.write( "Use point slope formula<BR>\n" );
document.write( "y+2/3 = -2 (x-1/2)\r<BR>\n" );
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document.write( "y= -2x +1 - (2/3)\r<BR>\n" );
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document.write( "y= -2x +(1/3)\r<BR>\n" );
document.write( "\n" );
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document.write( "</TD></TR></TABLE>\n" );