document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=973842>Question 973842</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the instantaneous rate of change of f(x)=x^2-8/3x+4 at x=-3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #595886 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=595886\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the instantaneous rate of change of f(x)=x^2-8/3x+4 at x=-3<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "If it's f(x)= (x^2-8)/(3x+4):<BR>\n" );
document.write( "f(x) = (x^2-8)*(3x+4)^-1<BR>\n" );
document.write( "f'(x) = 2x*(3x+4)^-1 + (x^2-8)*(-1)*(3x+4)^-2 * 3<BR>\n" );
document.write( "f'(x) = 2x/(3x+4) - 3(x^2-8)/(3x+4)^2<BR>\n" );
document.write( "---<BR>\n" );
document.write( "f'(-3) = -6/(-5) - 3*1/25<BR>\n" );
document.write( "= 27/25 = 1.08<BR>\n" );
document.write( " </SPAN>\n" );
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