document.write( "Question 973807: please solve-
\n" ); document.write( "2.In a school there are total of 50 students in
\n" ); document.write( "class X, who are divided in three sections A, B
\n" ); document.write( "and C. Section A and B have equal no. of
\n" ); document.write( "students. All the students of the class wrote a
\n" ); document.write( "test. The average marks obtained by the
\n" ); document.write( "section A and B together is 52.5. The average
\n" ); document.write( "marks obtained by the section A and C together
\n" ); document.write( "is 60. The average marks obtained by the
\n" ); document.write( "section B and C together is 70. The average
\n" ); document.write( "marks obtained by the students of sections A,
\n" ); document.write( "B and C together is 60. How many Students are
\n" ); document.write( "there in Section C.
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Algebra.Com's Answer #595869 by JoelSchwartz(130)\"\" \"About 
You can put this solution on YOUR website!
A=number of students in section A of class x
\n" ); document.write( "B=number of students in section B of class x
\n" ); document.write( "C=number of students in section C of class x
\n" ); document.write( "A=B
\n" ); document.write( "y=total marks for section A
\n" ); document.write( "z=total marks for section B
\n" ); document.write( "w=total marks for section C
\n" ); document.write( "A+B+C=50
\n" ); document.write( "2A+C=50
\n" ); document.write( "Two times the number of students in section A plus the number of students in section C equals 50 students.
\n" ); document.write( "(y+z)/2A=52.5
\n" ); document.write( "The total points for section A and B divided by the number of students in section A plus B.
\n" ); document.write( "(y+w)/(A+C)=60
\n" ); document.write( "(z+w)/(B+C)=70
\n" ); document.write( "(y+z+w)/(2A+C)=60\r
\n" ); document.write( "\n" ); document.write( "y+z=105A
\n" ); document.write( "(105A+w)/(2A+c)=60
\n" ); document.write( "2A+C=50
\n" ); document.write( "2A=50-C
\n" ); document.write( "(105A+w)/50=60
\n" ); document.write( "105A+w=3000
\n" ); document.write( "w=3000-105A
\n" ); document.write( "(y+3000-105A)/(50-A)=60
\n" ); document.write( "y+3000-105A=3000-60A
\n" ); document.write( "y=45A
\n" ); document.write( "45A+z=105A
\n" ); document.write( "z=60A
\n" ); document.write( "(60A+3000-105A)/(50-A)=70
\n" ); document.write( "-45A+3000=3500-70A
\n" ); document.write( "25A=500
\n" ); document.write( "A=20
\n" ); document.write( "40+C=50
\n" ); document.write( "C=10
\n" ); document.write( "There are ten students in sections C.\r
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