document.write( "Question 973807: please solve-
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document.write( "2.In a school there are total of 50 students in
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document.write( "class X, who are divided in three sections A, B
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document.write( "and C. Section A and B have equal no. of
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document.write( "students. All the students of the class wrote a
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document.write( "test. The average marks obtained by the
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document.write( "section A and B together is 52.5. The average
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document.write( "marks obtained by the section A and C together
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document.write( "is 60. The average marks obtained by the
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document.write( "section B and C together is 70. The average
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document.write( "marks obtained by the students of sections A,
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document.write( "B and C together is 60. How many Students are
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document.write( "there in Section C.
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Algebra.Com's Answer #595869 by JoelSchwartz(130)![]() ![]() ![]() You can put this solution on YOUR website! A=number of students in section A of class x \n" ); document.write( "B=number of students in section B of class x \n" ); document.write( "C=number of students in section C of class x \n" ); document.write( "A=B \n" ); document.write( "y=total marks for section A \n" ); document.write( "z=total marks for section B \n" ); document.write( "w=total marks for section C \n" ); document.write( "A+B+C=50 \n" ); document.write( "2A+C=50 \n" ); document.write( "Two times the number of students in section A plus the number of students in section C equals 50 students. \n" ); document.write( "(y+z)/2A=52.5 \n" ); document.write( "The total points for section A and B divided by the number of students in section A plus B. \n" ); document.write( "(y+w)/(A+C)=60 \n" ); document.write( "(z+w)/(B+C)=70 \n" ); document.write( "(y+z+w)/(2A+C)=60\r \n" ); document.write( "\n" ); document.write( "y+z=105A \n" ); document.write( "(105A+w)/(2A+c)=60 \n" ); document.write( "2A+C=50 \n" ); document.write( "2A=50-C \n" ); document.write( "(105A+w)/50=60 \n" ); document.write( "105A+w=3000 \n" ); document.write( "w=3000-105A \n" ); document.write( "(y+3000-105A)/(50-A)=60 \n" ); document.write( "y+3000-105A=3000-60A \n" ); document.write( "y=45A \n" ); document.write( "45A+z=105A \n" ); document.write( "z=60A \n" ); document.write( "(60A+3000-105A)/(50-A)=70 \n" ); document.write( "-45A+3000=3500-70A \n" ); document.write( "25A=500 \n" ); document.write( "A=20 \n" ); document.write( "40+C=50 \n" ); document.write( "C=10 \n" ); document.write( "There are ten students in sections C.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |