document.write( "Question 973793: If X=logbase 24 12;y=logbase36 24;z=logbase48 36 then
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document.write( "xyz+1 = ?
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document.write( "a) 2xy b) 2zx c) 2yz \n" );
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Algebra.Com's Answer #595855 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Use change of base formula \n" ); document.write( "log 12/log 24 =0.7819 \n" ); document.write( "log 24/log 36 =0.8868 \n" ); document.write( "log 36/log48 =0.9257 \n" ); document.write( "Product +1 =1.6418\r \n" ); document.write( "\n" ); document.write( "2xy=1.3868 \n" ); document.write( "2zx=1.447 \n" ); document.write( "2yz= 1.6418\r \n" ); document.write( "\n" ); document.write( "Alternatively, \n" ); document.write( "change base to 48\r \n" ); document.write( "\n" ); document.write( "[log48 (24)/log48 (12)]* log48 (36)/log48 (24) * [log 48 (36)] everything cancels but log 48 (24), and change of base formula gives same product as above. \r \n" ); document.write( "\n" ); document.write( "2xy=log24 (144)*log 36 (24) =[ log 36 (144)/log 36 (24)}*log base36 (24)= log36 (144) \n" ); document.write( "2yz=log36 (576)*log48 (36)= [log 48 (576)/log48 (36)] log 48 (36) =log 48 (576), etc. Think change base to 10 and solving it that way is easier. \n" ); document.write( " \n" ); document.write( " |