document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=973754>Question 973754</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve this question :<BR>\n" );
document.write( "find the values of 'a' and 'b' :<BR>\n" );
document.write( "3+sqrt(2)/ 3-sqrt(2) = a+b sqrt(2)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #595829 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=595829\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3+sqrt(2)/ 3-sqrt(2) = a+b sqrt(2)<BR>\n" );
document.write( "(3+sqrt(2)/ 3-sqrt(2)) * ((3+sqrt(2) / 3+sqrt(2)) =<BR>\n" );
document.write( "(9+6sqrt(2)+2) / (9 - 2) = <BR>\n" );
document.write( "(11+6sqrt(2) / 7) = <BR>\n" );
document.write( "(11/7) + (6/7)sqrt(2), therefore<BR>\n" );
document.write( "a = 11/7 and b = 6/7<BR>\n" );
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