document.write( "Question 973654: A woman can bicycle 20 miles in the same time that it takes her to jog 10 miles. If she can ride 5 mph faster than she can jog, how fast can she jog? \n" ); document.write( "
Algebra.Com's Answer #595763 by stanbon(75887)\"\" \"About 
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A woman can bicycle 20 miles in the same time that it takes her to jog 10 miles. If she can ride 5 mph faster than she can jog, how fast can she jog?
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\n" ); document.write( "Jog DATA::
\n" ); document.write( "dist = 10 miles ; rate = x mph ; time = d/r = 10/x hrs
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\n" ); document.write( "Bike DATA:
\n" ); document.write( "dist = 20 miles ; rate = x+5 mph ; rime = 20/(x+5) hrs
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\n" ); document.write( "Equation:
\n" ); document.write( "time = time
\n" ); document.write( "10/x = 20/(x+5)
\n" ); document.write( "10x + 50 = 20x
\n" ); document.write( "10x = 50
\n" ); document.write( "x = 5 mph (jogging rate)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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