document.write( "Question 973654: A woman can bicycle 20 miles in the same time that it takes her to jog 10 miles. If she can ride 5 mph faster than she can jog, how fast can she jog? \n" ); document.write( "
Algebra.Com's Answer #595763 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A woman can bicycle 20 miles in the same time that it takes her to jog 10 miles. If she can ride 5 mph faster than she can jog, how fast can she jog? \n" ); document.write( "-------------- \n" ); document.write( "Jog DATA:: \n" ); document.write( "dist = 10 miles ; rate = x mph ; time = d/r = 10/x hrs \n" ); document.write( "---- \n" ); document.write( "Bike DATA: \n" ); document.write( "dist = 20 miles ; rate = x+5 mph ; rime = 20/(x+5) hrs \n" ); document.write( "-------- \n" ); document.write( "Equation: \n" ); document.write( "time = time \n" ); document.write( "10/x = 20/(x+5) \n" ); document.write( "10x + 50 = 20x \n" ); document.write( "10x = 50 \n" ); document.write( "x = 5 mph (jogging rate) \n" ); document.write( "----------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------- \n" ); document.write( " |