document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=973653>Question 973653</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For a fixed voltage, the current in an electrical circuit varies inversely as the resistance in the circuit. If a certain circuit has a current of <BR>\n" );
document.write( "2 1/2 amps when the resistance is 140 ohms, find the current in the circuit when the resistance is doubled.<BR>\n" );
document.write( "  amps </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #595762 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=595762\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> E=IR<BR>\n" );
document.write( "I=E/R   This is the formula, and it is inversely.\r<BR>\n" );
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document.write( "2.5 amps=350 volts/140 ohms.  Now double the resistance, and you would expect the current to halve.\r<BR>\n" );
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document.write( "x= 350 volts/280 ohms\r<BR>\n" );
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document.write( "=1.25 amperes.\r<BR>\n" );
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document.write( "It indeed is half as much. </SPAN>\n" );
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