document.write( "Question 973501: Please help me solve this equation: logx(12) = 3 \n" ); document.write( "
Algebra.Com's Answer #595670 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"log%28x%2C%2812%29%29+=+3\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"12+=+x%5E3\" Convert to exponential form\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E3=12\" Flip the equation\r
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\n" ); document.write( "\n" ); document.write( "\"root%283%2Cx%5E3%29=root%283%2C12%29\" Take the cube root of both sides to isolate x.\r
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\n" ); document.write( "\n" ); document.write( "\"x=root%283%2C12%29\" Exact answer (in terms of radicals)\r
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\n" ); document.write( "\n" ); document.write( "\"x=12%5E%281%2F3%29%5E%22%22\" Exact answer (in terms of rational exponents)\r
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\n" ); document.write( "\n" ); document.write( "\"x=2.289428485\" Approximate answer (after typing in 12^(1/3) into a calculator; see note below)\r
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\n" ); document.write( "\n" ); document.write( "Note: The last link directs you to a calculator.
\n" ); document.write( "Once you get to the link, hit the \"=\" button to have the calculator compute the expression.
\n" ); document.write( "This will give you the approximate value of x.
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