document.write( "Question 973434: I would like to know how to answer this probability question\r
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document.write( "Weekly demand for an item is distributed normally with a mean of 630, and a standard deviation of 50. If you stocked exactly the mean of demand what is the probability that demand will exceed what you have in stock. Then question 2 is what is the probability of the demand exceeding what you stock if you stock 10% over the mean demand \n" );
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Algebra.Com's Answer #595624 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! mean=630 sd=50 \n" ); document.write( "The first is 50%\r \n" ); document.write( "\n" ); document.write( "z= (value-mean)/sd \n" ); document.write( "But value=mean, so z=0, and that is at the midpoint of the probability curve.\r \n" ); document.write( "\n" ); document.write( "z=(693-630)/50 ;; 10% over the mean demand is 10%of 630 (63) added to 630. \n" ); document.write( "z=63/50= +1.26 \n" ); document.write( "The probability wanted is that of z>1.26 This is relatively small, and in fact it is 0.104 \n" ); document.write( " |