document.write( "Question 972587: A party of 6 is to be formed from 10 men and 7 women so as to include 3 men and 3 women. In how many ways the party can be formed if two particular women refuse to join it? \n" ); document.write( "
Algebra.Com's Answer #595591 by Edwin McCravy(20055)\"\" \"About 
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A party of 6 is to be formed from 10 men and 7 women so as to include 3 men and
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document.write( "Then those 2 women are totally out of the picture, so we just ignore them and\r\n" );
document.write( "rewrite the problem without them, and include only the 5 other women:\r\n" );
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\n" ); document.write( "A party of 6 is to be formed from 10 men and 5 women so as to include 3 men and
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document.write( "We choose the men:\r\n" );
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document.write( "10 men Choose 3 = 10C3 = \"%2810%2A9%2A8%29%2F%283%2A2%2A1%29\" = 120 ways.\r\n" );
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document.write( "For each of those 120 ways to choose the men,\r\n" );
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document.write( "we choose the women:\r\n" );
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document.write( "5 women Choose 3 = 5C3 = \"%285%2A4%2A3%29%2F%283%2A2%2A1%29\" = 10 ways.\r\n" );
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document.write( "That's (120)(10) = 1200 ways.\r\n" );
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document.write( "[Note: I'm puzzled as to why a problem would bother just to exclude 2 women.\r\n" );
document.write( "Are you sure that the problem didn't say that they despise each other and that\r\n" );
document.write( "either one can be invited but not both?  That would change the answer.]\r\n" );
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document.write( "Edwin
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