document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=973373>Question 973373</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man is four times as old as his son. In five years time he will be three times as old. Find their present ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #595566 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=595566\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = age of son now<BR>\n" );
document.write( "4x = age of man now\r<BR>\n" );
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document.write( "x + 5 = age of son in five years<BR>\n" );
document.write( "4x + 5 = age of man in five years\r<BR>\n" );
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document.write( "4x + 5 = 3(x + 5) {in five years the man will be three times the son}<BR>\n" );
document.write( "4x + 5 = 3x + 15 {used distributive property}<BR>\n" );
document.write( "x + 5 = 15 {subtracted 3x from each side}<BR>\n" );
document.write( "x = 10 {subtracted 5 from each side}<BR>\n" );
document.write( "4x = 40 {substituted 10, in for x, into 4x}\r<BR>\n" );
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document.write( "son is 10<BR>\n" );
document.write( "man is 40<BR>\n" );
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