document.write( "Question 973143: Two ships are out in a storm in the ocean. The captain of the ship that is farthest out sees a lighthouse on shore. The angle of elevation in looking to the top of the lighthouse is 4 degrees. The light house is 100 m in height.From a second ship that is closer to the lighthouse the angle of elevation looking up at the tower is 6 degrees. Use this information to determine how far apart the two ships are.Please draw a diagram also.\r
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Algebra.Com's Answer #595532 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Two ships are out in a storm in the ocean.
\n" ); document.write( " The captain of the ship that is farthest out sees a lighthouse on shore.
\n" ); document.write( " The angle of elevation in looking to the top of the lighthouse is 4 degrees.
\n" ); document.write( " The light house is 100 m in height.
\n" ); document.write( " From a second ship that is closer to the lighthouse the angle of elevation looking up at the tower is 6 degrees.
\n" ); document.write( " Use this information to determine how far apart the two ships \r
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\n" ); document.write( "100
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\n" ); document.write( "_________a__________6\______________4\______
\n" ); document.write( "|-------------------------A---------------------------|\r
\n" ); document.write( "\n" ); document.write( "You find the leg of each right triangle using the law of sines
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\n" ); document.write( "The small triangle, find the 3rd angle 180 - 90 - 6 = 94
\n" ); document.write( "\"a%2Fsin%2894%29\" = \"100%2Fsin%286%29\"
\n" ); document.write( "\"a%2F.99756\" = \"100%2F.10453\"
\n" ); document.write( "cross multiply
\n" ); document.write( ".10453a = 100*.99756
\n" ); document.write( "a = \"99.756%2F.10453\"
\n" ); document.write( "a = 954.3 m from the lighthouse is the nearby ship
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\n" ); document.write( "The larger triangle, find the 3rd angle 180 - 90 - 4 = 96
\n" ); document.write( "\"A%2Fsin%2896%29\" = \"100%2Fsin%284%29\"
\n" ); document.write( "\"A%2F.99452\" = \"100%2F.069756\"
\n" ); document.write( "cross multiply
\n" ); document.write( ".069756A = 100*.99452
\n" ); document.write( "A = \"99.452%2F.069756\"
\n" ); document.write( "A = 1430.1 m from the lighthouse is the further ship
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\n" ); document.write( "The distance between the ships: 1430.1 - 954.3 = 475.8 meters
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\n" ); document.write( "You better check my math here.\r
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