document.write( "Question 973289: Anita is 3/4 the age of Judy. 4 years ago, she was 2/3s the age of Judy. How old is each? \n" ); document.write( "
Algebra.Com's Answer #595515 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "J=Judy's age; A=Anita's age=(3/4)J=0.75J \n" ); document.write( "A-4yrs=(2/3)(J-4yrs) Substitute for A \n" ); document.write( "(3/4)J-4yrs=(2/3)(J-4yrs) Multiply each side by 3/2. \n" ); document.write( "(9/8)J-6yrs=J-4yrs Add 5 yrs to each side. \n" ); document.write( "(9/8)J=J+2yrs Subtract J from each side. \n" ); document.write( "(1/8)J=2yrs Multiply each side by 8. \n" ); document.write( "J=16yrs ANSWER 1: Judy is 16 years old. \n" ); document.write( "A=(3/4)J=(3/4)16yrs=12 yrs ANSWER 2: Anita is 12 years old. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "A-4yrs=(2/3)(J-4yrs) \n" ); document.write( "12yrs-4yrs=(2/3)(16yrs-4yrs) \n" ); document.write( "8yrs=(2/3)(12yrs) \n" ); document.write( "8yrs=8yrs \n" ); document.write( " \n" ); document.write( " |