document.write( "Question 973286: Your $750 rent increases 3% over year. Write an equation and then find your rent in 10 years.\r
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document.write( "Doing this the long way (taking 750(0.03) and then changing the new rent amount each month, I come up with the rent totaling $1007.94 after 10 years. I can't figure out how to write that equation in a simpler form,and I'm not even sure I found the correct answer! \n" );
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Algebra.Com's Answer #595508 by Theo(13342)![]() ![]() You can put this solution on YOUR website! it would be 750 * 1.03^10 = 1007.937285\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you got it right, but you did it the long way.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the equation is derived as follows:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "750 * 1.03 gets you the first year.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "750 * 1.03 * 1.03 gets you the second year. \n" ); document.write( "that's equivalent to 750 * 1.03^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "750 * 1.03 * 1.03 * 1.03 gets you the third year. \n" ); document.write( "that's equivalent to 750 * 1.03^3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the tenth year becomes 750 * 1.03^10.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your multiplication factor is 1.03 because 750 + 750 * .03 is equal to 750 * 1.03 after you factor out the common term of 750. \n" ); document.write( " \n" ); document.write( " |