document.write( "Question 11519: I get really lost on square roots and simplifying them
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document.write( "for example (3h-7)^2 = 32 then 3h-7= or- the square root of 32, then 3h=7 +or- the square root of 32, which is h= 7 +or- the square root of 32. Here is where I get extremly lost: how does h=7+or- the square root of 32 become: h= 7 +or- 4 the square root of 2 over 3 Please explain this last step to me. If I can understand why this happens then maybe I'll understand what is going on. I have been on this particular problem for two weeks and no one every puts it in terms I can understand. Why and how does this happen.
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document.write( "-Sarah \n" );
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Algebra.Com's Answer #5955 by askmemath(368)![]() ![]() ![]() You can put this solution on YOUR website! Square root of a number N is a number n which when multiplied by itself will give you back N \n" ); document.write( "nxn = N\r \n" ); document.write( "\n" ); document.write( "e.g. \n" ); document.write( "5x5 = 25 so square root of 25 is 5 \n" ); document.write( "6x6 = 36 so sq root of 36 = 6 \n" ); document.write( "49 = 7x7 so 7 is the sq root of 49\r \n" ); document.write( "\n" ); document.write( "Now sq root of 32: \n" ); document.write( "32 = 4x8 \n" ); document.write( "8 = 4x2 \n" ); document.write( "32 = 4x4x2 \n" ); document.write( "Sq root of this = 4Root(2)\r \n" ); document.write( "\n" ); document.write( "So h = 7 +or - 4Root(2) \n" ); document.write( " |