document.write( "Question 973229: What is the smallest of three consecutive positive numbers if the product of the first and third is one less than eight times the second? \n" ); document.write( "
Algebra.Com's Answer #595482 by crystal5213(2)![]() ![]() ![]() You can put this solution on YOUR website! The smallest number is equal to 7.\r \n" ); document.write( "\n" ); document.write( "Explanation:\r \n" ); document.write( "\n" ); document.write( "For this problem, I'll be using variables to represent the numbers: x, y, and z. But since they are consecutive, y=x+1, and z=x+2, so the numbers can be written as x, x+1, and x+2. \r \n" ); document.write( "\n" ); document.write( "According to the problem, the product of the first and third number ( \n" ); document.write( "We can set the problem up like this: \n" ); document.write( " \n" ); document.write( "Now we can solve it like an algebraic equation instead of a word problem. Start by moving the variable to one side of the equation by subtracting 8x from both sides, resulting in: \n" ); document.write( " \n" ); document.write( "Since there is a variable squared, we should use the quadratic formula. So we will have to subtract 7 as well, so that 0 will be on one side of the equal sign. \n" ); document.write( " \n" ); document.write( "According to the quadratic equation, if \n" ); document.write( "Now, we plug in the numbers. \n" ); document.write( " \n" ); document.write( "in this case, a equals one because there is no number before \n" ); document.write( "Finally, after using a calculator to solve the equation, we get \n" ); document.write( " |