document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=973237>Question 973237</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am really frustrated with this problem, can you help me?\r<BR>\n" );
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document.write( "5/x+7 + 4/x-3 = x-11/x^2+4x-21\r<BR>\n" );
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document.write( "My first step was to factor the equation x^2+4x-21 which I found to give me (x+7)(x-3). but now I don't know where to go from here. I would appreciate your assistance. Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #595472 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=595472\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Multiply the whole equation by x^2+4x-21, written as (x-3)(x+7) as you have.\r<BR>\n" );
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document.write( "The first term  has the x+7 cancel<BR>\n" );
document.write( "it is 5(x-3).  The second term has the x-3 cancel and is 4(x+7).  The answer is now x-11\r<BR>\n" );
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document.write( "Distribute, and you have  5x-15  + 4x +28=x-11<BR>\n" );
document.write( "9x+13=x-11<BR>\n" );
document.write( "8x=-24<BR>\n" );
document.write( "x= -3\r<BR>\n" );
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document.write( "(5/4) -(4/6) = -14/24\r<BR>\n" );
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document.write( " </SPAN>\n" );
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