document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=973233>Question 973233</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bill can mow a lawn in 2 hours, working with Tom they can mow the same lawn in 1.5 hours.  How long would it take Tom working alone?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #595462 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=595462\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In one hour, Bill mows (1/2) of the lawn, and with Tom can mow (1/1.5)  of the lawn.\r<BR>\n" );
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document.write( "Together, they can mow, in one hour (1/2) + (1/x)=(1/1.5)\r<BR>\n" );
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document.write( "Multiply everything by 6x to clear fractions.\r<BR>\n" );
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document.write( "3x+6=4x<BR>\n" );
document.write( "x=6 hours.  It takes Tom 6 hours to mow the lawn.  In one hour the two mow (1/2)+(1/6)=2/3.  In the next half hour, they mow (1/4)+ (1/12)=(1/3), that finishes it up. </SPAN>\n" );
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