document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=973186>Question 973186</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Aldo put $400 into a savings account that paid an interest of 5.4% per year. What is the total amount in his account at the end of 1 year?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #595456 by </B><A HREF=/tutors/aboutme.mpl?userid=farohw><B>farohw(175)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=farohw><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=farohw><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=595456\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To find the amount we use the formula A = P(1 + rt) where \r<BR>\n" );
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document.write( "P is the Principal = $400\r<BR>\n" );
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document.write( "r is the interest rate 5.4% or 5.4/100 = 0.054 per year\r<BR>\n" );
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document.write( "and of course t is time = 1 year\r<BR>\n" );
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document.write( "Therefore, A = 400(1 + 0.054(1)) = $421.60\r<BR>\n" );
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document.write( "and this is the total amount he will have at the end of one year.<BR>\n" );
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