document.write( "Question 973215: How do you find the equation of a circle if it lies in the first quadrant and is tangent to x=-3 y=3 and x=11 \n" ); document.write( "
Algebra.Com's Answer #595438 by Alan3354(69443)\"\" \"About 
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How do you find the equation of a circle if it lies in the first quadrant and is tangent to x=-3 y=3 and x=11
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\n" ); document.write( "Tangent to x=-3 and x=11 makes the diameter 14 --> r = 7
\n" ); document.write( "and the center is (4,y)
\n" ); document.write( "7 units from y=3 --> y = -4 or y = 10
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\n" ); document.write( "In Q1 --> y = 10
\n" ); document.write( "--> center at (4,10)
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\n" ); document.write( "\"%28x-4%29%5E2+%2B+%28y-10%29%5E2+=+49\" is the circle
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