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y=3x
\n" ); document.write( "or
\n" ); document.write( "y=3x+0
\n" ); document.write( "Compared to the equation of a line formula:
\n" ); document.write( "y=mx+b
\n" ); document.write( "y=any y value
\n" ); document.write( "m=the slope of the line
\n" ); document.write( "x=any corresponding x-value
\n" ); document.write( "b=the point where the line intersects the y-axis
\n" ); document.write( "For y=3x+0,
\n" ); document.write( "the line will cross or intersect the y=axis at (0, 0), starting from that point, use the slope of 3 or 3/1. That is, from (0, 0,) go up +3 and over +1 and plot that point (1,3)
\n" ); document.write( "From (1, 3) go up +3 and over +1 and plot that point (2, 6).
\n" ); document.write( ".
\n" ); document.write( "Now for the bottom of the graph, start again at (0, 0), and using the slope
\n" ); document.write( "-3/-1 (same as +3), go down -3 and to the left (-1); plot this point (-1, -3).
\n" ); document.write( "Repeat this pattern by going down -3 and over to the left -1; plot this point (-2, -6).
\n" ); document.write( ".
\n" ); document.write( "Connect the lines.
\n" ); document.write( ".\r
\n" ); document.write( "\n" ); document.write( "y=x+3
\n" ); document.write( "or y=1x+3
\n" ); document.write( "The slope = 1 or 1/1
\n" ); document.write( "The line crosses or intersects the y-axis at (0, 3)
\n" ); document.write( "So, repeat the instructions from above, only start at point (0, 3) and go up 1 and over 1, etc.
\n" ); document.write( "Graphing:
\n" ); document.write( "