document.write( "Question 973113: If alpha and beta are the zeroes of the polynomial p(x)=9x^2-22x+8 then find the value of alpha ^4+beta ^4 \n" ); document.write( "

Algebra.Com's Answer #595363 by Boreal(15235) $\"\"$ $\"About$

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9x^2-22x+8=0 Multiply the 8 by the leading coefficient, and rewrite leading coefficient as 1.\r
\n" ); document.write( "\n" ); document.write( "x^2-22x+72=0; factor into (x-18)(x-4)=0 divide now by the 9 you multiplied by, reducing all fractions.
\n" ); document.write( "(x-(18/9)) (x-(4/9))=0\r
\n" ); document.write( "\n" ); document.write( "(x-2) (9x-4)=0 are factors. They multiply out to the original polynomial.\r
\n" ); document.write( "\n" ); document.write( "The quadratic formula also works
\n" ); document.write( "(1/18) [22 +/- sqrt (484- 288)]= (1/18) [22 +/- sqrt (196)]\r
\n" ); document.write( "\n" ); document.write( "(1/18) (22+14) ; (1/18) (22-14)
\n" ); document.write( "roots are 2 and 4/9, same as above.\r
\n" ); document.write( "\n" ); document.write( "will take smaller zero to be alpha (4/9)
\n" ); document.write( "(4/9)^4= (256/6561)
\n" ); document.write( "2^4=16
\n" ); document.write( "16.0390\r
\n" ); document.write( "\n" ); document.write( " $\"graph+%28300%2C300%2C-3%2C3%2C-10%2C10%2C9x%5E2-22x%2B8%29\"$ \n" ); document.write( "

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