document.write( "Question 973110: The area of a rectangular restaurant kitchen is 80 square meters. The perimeter is 36 meters. What are the dimensions of the kitchen? \n" ); document.write( "
Algebra.Com's Answer #595360 by macston(5194)\"\" \"About 
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L=length; W=width
\n" ); document.write( "P=2(L+W)
\n" ); document.write( "36m=2(L+W)
\n" ); document.write( "18m=L+W
\n" ); document.write( "18m-W=L Use this to substitute for L.
\n" ); document.write( ".
\n" ); document.write( "\"A=LW\" Substitute for L.
\n" ); document.write( "\"80m%5E2=%2818m-W%29%28W%29\"
\n" ); document.write( "\"80m%5E2=18W-W%5E2\"
\n" ); document.write( "\"0=-W%5E2%2B18W-80\"
\n" ); document.write( "\"0=W%5E2-18W%2B80\"
\n" ); document.write( "\"0=%28W-8%29%28W-1%29\"
\n" ); document.write( "\"W-8=0\" \"or\" \"W-10=0\"
\n" ); document.write( "\"W=8\" \"or\" \"W=10\"
\n" ); document.write( "When width=8m, length=18m-w=18m-8m=10m.
\n" ); document.write( "When width=10m length=18m-10m=8m
\n" ); document.write( "Dimensions are either 8m x 10m or 10m x 8m.\r
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