document.write( "Question 973074: Jen Butler has been pricing speed pass train fares for a group trip to new york. Three adults and four children must pay $100.00. Two adults and three children must pay $70.00.Find the price of the adults ticket and the price of the childs ticket. \n" ); document.write( "
Algebra.Com's Answer #595356 by macston(5194)![]() ![]() You can put this solution on YOUR website! A=Adult price; C=Child price \n" ); document.write( "3A+4C=$100 Multiply by 2. \n" ); document.write( "6A+8C=$200 Use this to subtract below. \n" ); document.write( ". \n" ); document.write( "2A+3C=$70 Multiply by 3. \n" ); document.write( ". 6A+9C=$210 Subtract equation from above. \n" ); document.write( "-(6A+8C=$200) \n" ); document.write( "C=$10 ANSWER 1: One child's fare is $10 \n" ); document.write( ". \n" ); document.write( "3A+4C=$100 \n" ); document.write( "3A+4($10)=$100 \n" ); document.write( "3A+$40=$100 \n" ); document.write( "3A=$60 \n" ); document.write( "A=$20 ANSWER 2: One adult's fare is $20 \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "2A+3C=$70 \n" ); document.write( "2($20)+3($10)=$70 \n" ); document.write( "$40+$30=$70 \n" ); document.write( "$70=$70\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |