document.write( "Question 972914: 1. Adjacent sides of parallelogram are 7cm and 9cm. Its 1 diagonal is 8cm. Find its other diagonal.
\n" ); document.write( "2. Diagonals of parallelogram are 12cm and 26cm. One of its side is 17cm. Find the other side.
\n" ); document.write( "

Algebra.Com's Answer #595334 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
1. Adjacent sides of parallelogram are 7cm and 9cm. Its 1 diagonal is 8cm. Find its other diagonal.
\n" ); document.write( "Two adjacent sides and that diagonal form a triangle,
\n" ); document.write( "with the angle between those two sides opposite that diagonal.
\n" ); document.write( "
\n" ); document.write( "The law of cosines says that for a triangle with vertices A, B, and C,
\n" ); document.write( "opposite sides a, b, and c respectively,
\n" ); document.write( "the measures of angles and sides are related by
\n" ); document.write( "\"a%5E2=b%5E2%2Bc%5E2-2bc%2Acos%28A%29\" .
\n" ); document.write( "
\n" ); document.write( "There is a triangle formed by
\n" ); document.write( "two sides measuring \"b=7\"cm and \"c=9\"cm flanking angle \"A\" ,
\n" ); document.write( "and a diagonal measuring \"a=8\"cm, connected to both of those sides.
\n" ); document.write( "That triangle, with sides so similar in length, must be an acute triangle.
\n" ); document.write( "Applying law of cosines to that triangle, we write
\n" ); document.write( "\"8%5E2=7%5E2%2B9%5E2-2%2A7%2A9%2Acos%28A%29\"
\n" ); document.write( "\"64=49%2B81-2%2A7%2A9%2Acos%28A%29\"
\n" ); document.write( "\"2%2A7%2A9%2Acos%28A%29=49%2B81-64\"
\n" ); document.write( "\"126cos%28A%29=66\"
\n" ); document.write( "\"cos%28A%29=66%2F126=11%2F21\" .
\n" ); document.write( "The cosine is positive, meaning that \"A\" is an acute angle.
\n" ); document.write( "In fact, \"A=about58.4%5Eo\" , but we do not need to calculate that.
\n" ); document.write( "The parallelogram looks like this:
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "The other diagonal \"d\" is opposite the other angle of the parallelogram, the angle at D,
\n" ); document.write( "which is supplementary to angle A, so that \"cos%28D%29=-cos%28A%29=-11%2F21\" ,
\n" ); document.write( "and is also flanked by sides measuring 7cm and 9cm.
\n" ); document.write( "Those sides and the other diagonal form another triangle.
\n" ); document.write( "
\n" ); document.write( "Applying law of cosines to that other triangle, we write
\n" ); document.write( "\"d%5E2=7%5E2%2B9%5E2-2%2A7%2A9%2Acos%28D%29=49%2B81-126%2A%28-11%2F21%29=49%2B81%2B66=196\"--->\"d=sqrt%28196%29=14\"
\n" ); document.write( "The other diagonal measures \"highlight%2814cm%29\" .
\n" ); document.write( "
\n" ); document.write( "2. Diagonals of parallelogram are 12cm and 26cm. One of its side is 17cm.Yhe \"x\"= length of the other side in cm.
\n" ); document.write( "Since the diagonals of a parallelogram bisect each other,
\n" ); document.write( "the longer diagonal will be split into two congruent segments,
\n" ); document.write( "each one measuring \"26cm%2F2=13cm\" ,
\n" ); document.write( "and the shorter diagonal will be split into two congruent segments,
\n" ); document.write( "each one measuring \"12cm%2F2=6cm\" .
\n" ); document.write( "Then, the parallelogram, divided into two pairs of congruent triangles, will look like this:
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "The law of cosines says that for a triangle with vertices A, B, and C,
\n" ); document.write( "opposite sides a, b, and c respectively,
\n" ); document.write( "the measures of angles and sides are related by
\n" ); document.write( "\"a%5E2=b%5E2%2Bc%5E2-2bc%2Acos%28A%29\" .
\n" ); document.write( "
\n" ); document.write( "To find \"x\" , we can apply law of cosines to the left side triangle and write
\n" ); document.write( "\"x%5E2=6%5E2%2B13%5E2-2%2A6%2A13%2Acos%28green%28X%29%29\" ,
\n" ); document.write( "but we do not know \"green%28X%29\" , or \"cos%28green%28X%29%29\" .
\n" ); document.write( "However, we know that \"red%28Y%29\" and \"green%28X%29\" are supplementary,
\n" ); document.write( "and that because of that \"cos%28red%28Y%29%29=-cos%28green%28X%29%29\" .
\n" ); document.write( "
\n" ); document.write( "We can find about \"cos%28red%28Y%29%29\" and \"cos%28green%28X%29%29\" by applying law of cosines to the top triangle:
\n" ); document.write( "\"17%5E2=6%5E2%2B13%5E2-2%2A6%2A13%2Acos%28red%28Y%29%29\"--->\"17%5E2=6%5E2%2B13%5E2%2B2%2A6%2A13%2Acos%28green%28X%29%29\"--->\"289=36%2B169%2B156%2Acos%28green%28X%29%29\"--->\"cos%28green%28X%29%29=%28289-36-169%29%2F156\"--->\"cos%28green%28X%29%29=%28289-36-169%29%2F156=84%2F156=7%2F13\" .
\n" ); document.write( "
\n" ); document.write( "Now we get back to the left triangle to find \"x\" :
\n" ); document.write( "\"x%5E2=6%5E2%2B13%5E2-2%2A6%2A13%2Acos%28green%28X%29%29\"--->\"x%5E2=36%2B169-156cos%28green%28X%29%29\"--->\"x%5E2=36%2B169-156cos%28green%28X%29%29\"--->\"x%5E2=36%2B169-156%287%2F13%29\"--->\"x%5E2=121\"--->\"x=sqrt%28121%29\"--->\"x=11\"
\n" ); document.write( "The other side measures \"highlight%2811cm%29\" .
\n" ); document.write( "
\n" );