document.write( "Question 973066: How do you do this decay problem?\r
\n" ); document.write( "\n" ); document.write( "The radioactive isotope 123I, used in nuclear imaging, decays continuously at a rate of 5.25% per hour.
\n" ); document.write( "(a) Approximate the percentage remaining of any initial amount after 26.4 hours.
\n" ); document.write( "(b) What is the half-life of 123I?\r
\n" ); document.write( "\n" ); document.write( "For part a I think the formula for that is A(t)=A*e^(kt). The problem that I'm having with this is that I don't know the initial amount (A). Here are the variables:\r
\n" ); document.write( "\n" ); document.write( "A=?
\n" ); document.write( "k=?
\n" ); document.write( "t=26.4\r
\n" ); document.write( "\n" ); document.write( "It seems like it's asking what (k) would be but I don't know how to solve for (k) without knowing the initial amount (A). I think I may be looking at it wrong. Any help on this one would be appreciated. I know how to do part b but I need to know how to do part a first before I can do b.\r
\n" ); document.write( "\n" ); document.write( "Thank you!!\r
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Algebra.Com's Answer #595330 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Retention is \"100-5.25=94.75\" percent each hour.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Starting with quantity 1, Using the model,
\n" ); document.write( "\"0.9475=1%2Ae%5E%28k%2A1%29\"
\n" ); document.write( "\"0.9475=e%5Ek\"
\n" ); document.write( "\"ln%280.9475%29=k%2A1\"
\n" ); document.write( "\"highlight%28k=ln%280.9475%29%29\" and the model is more specifically \"highlight_green%28A%28t%29=A%2Ae%5E%28-0.05393t%29%29\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "HALF-LIFE\r
\n" ); document.write( "\n" ); document.write( "\"%281%2F2%29=1%2Ae%5E%28-0.05393t%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"ln%281%2F2%29=-0.05393%2At%2Aln%28e%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"t=ln%281%2F2%29%2F%28-0.05393%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"highlight%28t=12.9%29\" hours
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