document.write( "Question 973064: A CARGO SHIP SETS OUT ON A RIVER WHO'S CURRENT IS 3 MPH. THE SHIP LEAVES THE DOCK GOING DOWN RIVER AND WILL RETURN TO THE SAME DOCK. HOW FAST CAN THE SHIP TRAVEL IN STILL WATER IF IT CAN TRAVEL TO A DOCK 112 MILES DOWN RIVER AND RETURN IN A TOTAL TRAVEL TIME OF 22 HOURS? (note: this 22 hours doesn't include time spent loading/unloading any cargo)\r
\n" ); document.write( "\n" ); document.write( "I need help formulating this equation!...please!\r
\n" ); document.write( "\n" ); document.write( "IS...
\n" ); document.write( "(112/x+3) + (112/x- 3)=22 ???? IS THAT EVEN CLOSE??\r
\n" ); document.write( "\n" ); document.write( "PLEASE ....how do i formulate an equation to answer this problem?
\n" ); document.write( "Thank you for your time and help!
\n" ); document.write( "With appreciation,
\n" ); document.write( "Ronald Adams
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Algebra.Com's Answer #595320 by Alan3354(69443)\"\" \"About 
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A CARGO SHIP SETS OUT ON A RIVER WHO'S CURRENT IS 3 MPH. THE SHIP LEAVES THE DOCK GOING DOWN RIVER AND WILL RETURN TO THE SAME DOCK. HOW FAST CAN THE SHIP TRAVEL IN STILL WATER IF IT CAN TRAVEL TO A DOCK 112 MILES DOWN RIVER AND RETURN IN A TOTAL TRAVEL TIME OF 22 HOURS? (note: this 22 hours doesn't include time spent loading/unloading any cargo)\r
\n" ); document.write( "\n" ); document.write( "I need help formulating this equation!...please!\r
\n" ); document.write( "\n" ); document.write( "IS...
\n" ); document.write( "(112/x+3) + (112/x- 3)=22 ???? IS THAT EVEN CLOSE??
\n" ); document.write( "=====================
\n" ); document.write( "That's correct.
\n" ); document.write( "Solve for x
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