document.write( "Question 973020: The perimeter of a rectangle is 34 inches, and its area is 60 square inches. What is the product of the lengths of the diagonals, in square inches?
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Algebra.Com's Answer #595299 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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The perimeter of a rectangle is 34 inches,
\n" ); document.write( "2L + 2W = 34
\n" ); document.write( "simplify, divide by 2
\n" ); document.write( "L + W = 17
\n" ); document.write( "L = (17-W)
\n" ); document.write( " and its area is 60 square inches.
\n" ); document.write( " L*W = 60
\n" ); document.write( "Find the dimensions, replace L with (17-W) in the area equation
\n" ); document.write( "W(17-W) = 60
\n" ); document.write( "-W^2 + 17W - 60 = 0
\n" ); document.write( "Multiply equation by -1
\n" ); document.write( "W^2 - 17W + 60 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(W-5)(W-12) = 0
\n" ); document.write( "W = 5, then L=12
\n" ); document.write( "W = 12, then L=5
\n" ); document.write( ":
\n" ); document.write( " What is the product of the lengths of the diagonals, in square inches?
\n" ); document.write( " $\"%28sqrt%2812%5E2%2B5%5E2%29%29%5E2\"$ = 144 + 25 = 169 sq inches \n" ); document.write( "

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