document.write( "Question 972982: A surface receiving sound is moved from its original position to a position three times farther away from the source of the sound. The intensity of the received sound thus becomes
\n" ); document.write( "A. three times as low.
\n" ); document.write( "B. three times as high.
\n" ); document.write( "C. nine times as high.
\n" ); document.write( "D. nine times as low. \r
\n" ); document.write( "\n" ); document.write( "I think it may be C nine times as high
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Algebra.Com's Answer #595294 by macston(5194)\"\" \"About 
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\n" ); document.write( "Sound varies with the inverse of the square of the distance. A distance three times farther yields:
\n" ); document.write( "\"intensity=1%2F%283%5E2%29\"
\n" ); document.write( "\"intensity=1%2F9\"
\n" ); document.write( "The intensity at the new distance is 1/9 the original intensity.
\n" ); document.write( "The given answers make no sense. Once you decrease an amount 1 time, nothing is left. I think the intended answer is D, but this, too, is wrong. If we take a quantity, say 1, and take nine times it we get 9. Now if we decrease the original 1 by nine times 1 we have 1-0=-8. So even answer D would imply after making the distance three times greater the sound intensity is -8 (if the original intensity is considered as 1). In general, the phrases \"three times as low\", \"three times smaller\", or \"three times less\" have no meaning. \r
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