document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=82938>Question 82938</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Fout tractors working together can plow a field in 12hrs.How long will it take six tractors to plow a field of the same size if all tractors work at same rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #59529 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=59529\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=time it takes for 6 tractors to plow the field.\r<BR>\n" );
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document.write( "Each tractor can plow the field at the rate of 1/4 of field per 12 hours. Or one tractor can plow the field(4/4)in 4*12=48 hours.  In other words, it takes 48 tractor-hours to plow the field.\r<BR>\n" );
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document.write( "So x=(Number of Tractor-Hours Required)/(Number of Tractors)-- in this case -6\r<BR>\n" );
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document.write( "1 tractor takes 48/1=48 hours<BR>\n" );
document.write( "2 tractors takes 48/2=24 hours<BR>\n" );
document.write( "3 tractors takes 48/3=16 hours<BR>\n" );
document.write( "4 tractors takes 48/4=12 hours<BR>\n" );
document.write( "6 tractors takes 48/6=8 hours-------------------------ans\r<BR>\n" );
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document.write( "Hope this helps----ptaylor </SPAN>\n" );
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