document.write( "Question 972979: Please help me solve/graph this!
\n" ); document.write( "f(x)= Log2(x+1)+2
\n" ); document.write( "thank you!
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Algebra.Com's Answer #595252 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Here's the graph:
\n" ); document.write( "\"+graph%28+400%2C+400%2C+-6%2C+6%2C+-6%2C+6%2C+log%28+2%2C+x%2B1+%29+%2B+2+%29+\"
\n" ); document.write( "The graph goes through ( 0, 2 ) since
\n" ); document.write( "\"+f%280%29+=+log%28+2%2C1+%29+%2B+2+\"
\n" ); document.write( "\"+f%280%29+=+0+%2B+2+\"
\n" ); document.write( "------------------
\n" ); document.write( "\"+x+\" can never be more negative than \"+-1+\" since
\n" ); document.write( "that would mean a log which gives you a negative number
\n" ); document.write( "which is impossible
\n" ); document.write( "--------------------
\n" ); document.write( "As \"+x+\" approaches \"+-1+\", \"+f%28x%29+\" becomes more
\n" ); document.write( "negative since
\n" ); document.write( "\"+log%28+2%2C+0+%29+\" = minus infinity
\n" ); document.write( "------------------------------
\n" ); document.write( "When \"+f%28x%29+=+0+\"
\n" ); document.write( "\"+0+=+log%28+2%2C+x%2B1+%29+%2B+2+\"
\n" ); document.write( "\"+log%28+2%2C+x%2B1+%29+=+-2+\"
\n" ); document.write( "\"+2%5E%28-2%29+=+x+%2B+1+\"
\n" ); document.write( "\"+1%2F4+=+x+%2B+1+\"
\n" ); document.write( "\"+x+=+-3%2F4+\"
\n" ); document.write( "which seems to agree with plot
\n" ); document.write( "Hope this helps
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