document.write( "Question 972977: The number of real roots of the equation
\n" ); document.write( "{(2x-3)/(x-1)}+1=(6x^2-x-6)/(x-1):
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Algebra.Com's Answer #595246 by macston(5194)\"\" \"About 
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\n" ); document.write( "\"%282x-3%29%2F%28x-1%29%2B1=%286x%5E2-x-6%29%2F%28x-1%29\"
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\n" ); document.write( "\"%282x-3%29%2F%28x-1%29%2B%28x-1%29%2F%28x-1%29=%286x%5E2-x-6%29%2F%28x-1%29\" Multiply by (x-1).
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\n" ); document.write( "\"2x-3%2Bx-1=6x%5E2-x-6\"
\n" ); document.write( "\"3x-4=6x%5E2-x-6\"
\n" ); document.write( "\"3x=6x%5E2-x-2\"
\n" ); document.write( "\"0=6x%5E2-4x-2\"
\n" ); document.write( "\"0=%28x-1%29%286x%2B2%29\"
\n" ); document.write( "\"x-1=0\" \"or\" \"6x%2B2=0\"
\n" ); document.write( "\"x=1\" \"or\" \"6x=-2\"
\n" ); document.write( "\"x=1\" \"or\" \"x=-1%2F3\"
\n" ); document.write( "Since x cannot equal 1 (division by 0)
\n" ); document.write( "ANSWER: x=-1/3
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