document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=972969>Question 972969</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many liters of a 48% solution should be added to 40 liters of a 35% solution if the final  mixture is to contain a 40% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #595237 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=595237\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=liters of 48% solution<BR>\n" );
document.write( "The trick in this is to remember the final solution is going to be 40 liters (the other part) +x added.\r<BR>\n" );
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document.write( ".48x +40(.35)=(40+x)*0.40\r<BR>\n" );
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document.write( ".48x + 14 =16 + 0.40x<BR>\n" );
document.write( "0.08x =2<BR>\n" );
document.write( "8x=200<BR>\n" );
document.write( "x=25 liters\r<BR>\n" );
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document.write( "total solution is 65 liters<BR>\n" );
document.write( "65(.40)=26   .48(25)=12  and 40 (.35)=14\r<BR>\n" );
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document.write( "25 liters of a 48% solution </SPAN>\n" );
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