document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=972950>Question 972950</A>: <I><SPAN STYLE=\"word-break: break-all;\"> suppose that the Lone Ranger can clean up all of the crime in the town of Fort Smith in 8 hours when working alone. Tonto can do the same job working alone in 12 hours. if Tonto starts fighting crime at 9am. and the Lone Ranger joins him at 11am. at what time they have all of the crime cleaned up in the town? Round your answer to the nearest minute. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #595203 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=595203\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "Lone Ranger: 100% of crime/8 hours=12.5% of crime per hour<BR>\n" );
document.write( "Tonto: 100% of crime/12 hours=8.33% of crime per hour<BR>\n" );
document.write( "If Tonto starts at 9 AM, at 11 AM there is (100% of crime-(2 hrs)(8.33%/hr))=<BR>\n" );
document.write( "100%-16.66%=83.33% of the crime left. <BR>\n" );
document.write( "Together, the two clean up 12.5%+8.33%=20.83% per hour<BR>\n" );
document.write( "83.33%/20.83%=4 hours. After the Lone Ranger joins Tonto (at 11 am), it will take them 4 hours to clean up the remaining 83.33% of the crime. Four hours from 11 AM is 3PM, so they will be finished at 3 PM.  </SPAN>\n" );
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