document.write( "Question 972955: Hello, i have this problem\r
\n" ); document.write( "\n" ); document.write( "Find a*b\r
\n" ); document.write( "\n" ); document.write( "a = 2i-j , b = j-3k\r
\n" ); document.write( "\n" ); document.write( "I've tried this so far: 2i-j*j-3k = 2i-3k-j
\n" ); document.write( "I feel like this is so wrong.\r
\n" ); document.write( "\n" ); document.write( "I'd appreciate an explanation on how to handle vectors with an \"i\", \"j\", \"k\" etc behind them. Also, what are these called?
\n" ); document.write( "Thanks\r
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Algebra.Com's Answer #595201 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Find \r
\n" ); document.write( "\n" ); document.write( "if \"a+=+2i-j\" and \"b+=+j-3k\", then \"a%2Ab=%282i-j%29%28+j-3k%29\"\r
\n" ); document.write( "\n" ); document.write( "recall the rule for multiplication of binomials:\r
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\n" ); document.write( "\n" ); document.write( "1. multiply each term in one binomial by each term in the other binomial
\n" ); document.write( "2. add those answers together, and simplify if needed
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\n" ); document.write( "so, you have:\r
\n" ); document.write( "\n" ); document.write( "\"a%2Ab=%282i-j%29%28+j-3k%29\"\r
\n" ); document.write( "\n" ); document.write( "\"a%2Ab=+2i%2Aj-2i%2A3k-j%2Aj-j%2A%28-3k%29\"\r
\n" ); document.write( "\n" ); document.write( "\"a%2Ab=+2ij-6ik-j%5E2%2B3jk\"\r
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