document.write( "Question 972953: Hello. I am beginning a unit on probability, and the question is as follows: \"Explain how the probability of an event differs from the odds in favor of the event when all outcomes are equally likely.\" However, I cannot see how they differ. For example, if I have a 6 sided die, and the event is rolling a 1, the probability is 1/6, and the odds in favor of it are also 1/6. Please help me! \n" ); document.write( "

Algebra.Com's Answer #595199 by macston(5194) $\"\"$ $\"About$

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\n" ); document.write( "Probability of x is given by :
\n" ); document.write( " $\"P%5Bx%5D=chances_for%2Ftotal_chances\"$
\n" ); document.write( "The probability of rolling the one is 1/6.
\n" ); document.write( "Odds are given by:
\n" ); document.write( "Odds=chances for:chances against
\n" ); document.write( "The chance of rolling a one is 1 in 6
\n" ); document.write( "The chance against rolling a 1 is (1-chance of rolling 1)=5/6
\n" ); document.write( "So odds of rolling a 1 :
\n" ); document.write( "1/6:5/6=1:5
\n" ); document.write( "1 to 5 (1 chance to roll a 1 to 5 chances of rolling something else)
\n" ); document.write( "The difference being probability uses total chances and odds use chances against. \n" ); document.write( "

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