document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=972919>Question 972919</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The diagram shows an ancient coin which was used in China. The coin is a circle of 3cm with a square of X Cm removed from its centre .<BR>\n" );
document.write( "(a) find an expression for the area of one side of the coin in terms of X and &#960;.<BR>\n" );
document.write( "(b) The area of one side of the coin is 7&#960;cm².<BR>\n" );
document.write( "Find the area of the square by performing an equation in x. <BR>\n" );
document.write( "(Take &#960; to be 3.14)\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #595180 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=595180\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "PART A:<BR>\n" );
document.write( "The question is unclear. We will assume X=side of square.<BR>\n" );
document.write( "If 3cm=radius of coin:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Area=%28pi%29r%5E2-X%5E2 ALIGN=MIDDLE  ALT=\"Area=%28pi%29r%5E2-X%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Area=%28pi%29%289cm%5E2%29-X%5E2 ALIGN=MIDDLE  ALT=\"Area=%28pi%29%289cm%5E2%29-X%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Area=9%28pi%29cm%5E2-X%5E2 ALIGN=MIDDLE  ALT=\"Area=9%28pi%29cm%5E2-X%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".<BR>\n" );
document.write( "If 3cm=diameter of coin:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Area=%28pi%29%281.5cm%29%5E2-X%5E2 ALIGN=MIDDLE  ALT=\"Area=%28pi%29%281.5cm%29%5E2-X%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Area=2.25%28pi%29cm%5E2-X%5E2 ALIGN=MIDDLE  ALT=\"Area=2.25%28pi%29cm%5E2-X%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".<BR>\n" );
document.write( "If 3cm=circumference of coin:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Area=%28pi%29%28C%2F2%28pi%29%29%5E2-X%5E2 ALIGN=MIDDLE  ALT=\"Area=%28pi%29%28C%2F2%28pi%29%29%5E2-X%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Area=%28pi%29%283cm%2F2%28pi%29%29%5E2-X%5E2 ALIGN=MIDDLE  ALT=\"Area=%28pi%29%283cm%2F2%28pi%29%29%5E2-X%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Area=%28pi%29%289cm%5E2%2F4%28pi%29%5E2%29-X%5E2 ALIGN=MIDDLE  ALT=\"Area=%28pi%29%289cm%5E2%2F4%28pi%29%5E2%29-X%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Area=9cm%5E2%2F4%28pi%29-X%5E2 ALIGN=MIDDLE  ALT=\"Area=9cm%5E2%2F4%28pi%29-X%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".<BR>\n" );
document.write( "PART B:<BR>\n" );
document.write( "Since 3cm as radius yields the only workable solution, we will use that as example:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Area=7%28pi%29cm%5E2 ALIGN=MIDDLE  ALT=\"Area=7%28pi%29cm%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Area=9%28pi%29cm%5E2-X%5E2 ALIGN=MIDDLE  ALT=\"Area=9%28pi%29cm%5E2-X%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=7%28pi%29cm%5E2=9%28pi%29cm%5E2-X%5E2 ALIGN=MIDDLE  ALT=\"7%28pi%29cm%5E2=9%28pi%29cm%5E2-X%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 7(pi)cm^2 from each side<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0=2%28pi%29cm%5E2-X%5E2 ALIGN=MIDDLE  ALT=\"0=2%28pi%29cm%5E2-X%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Add X^2 to each side.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=X%5E2=2%28pi%29cm%5E2 ALIGN=MIDDLE  ALT=\"X%5E2=2%28pi%29cm%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( " Since X=side of square, area of square=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=X%5E2=2%28pi%29cm%5E2 ALIGN=MIDDLE  ALT=\"X%5E2=2%28pi%29cm%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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