document.write( "Question 972925: 2 years ago I was 4 times my sons age. 8 years ago I was 10 times his age.
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Algebra.Com's Answer #595177 by macston(5194)\"\" \"About 
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\n" ); document.write( "Y=your age; S=son's age
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\n" ); document.write( "Y-2=4(S-2)
\n" ); document.write( "Y-2=4S-8
\n" ); document.write( "Y=4S-6 Use this to substitute for Y below.
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\n" ); document.write( "Y-8=10(S-8)
\n" ); document.write( "Y-8=10S-80
\n" ); document.write( "Y=10S-72 Substitute for Y from above.
\n" ); document.write( "4S-6=10S-72 Subtract 4S from each side.
\n" ); document.write( "-6=6S-72 Add 72 to each side.
\n" ); document.write( "66=6S
\n" ); document.write( "11=S ANSWER: The son is currently 11 years old.
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\n" ); document.write( "CHECK:
\n" ); document.write( "Y-2=4(S-2)
\n" ); document.write( "Y-2=4(11-2)
\n" ); document.write( "Y-2=4(9)
\n" ); document.write( "Y-2=36
\n" ); document.write( "Y=38 You are currently 38 years old
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\n" ); document.write( "Y-8=10(S-8)
\n" ); document.write( "38-8=10(11-8)
\n" ); document.write( "30=10(3)
\n" ); document.write( "30=30 \r
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