document.write( "Question 972925: 2 years ago I was 4 times my sons age. 8 years ago I was 10 times his age.
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document.write( "How old is he now? \n" );
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Algebra.Com's Answer #595177 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Y=your age; S=son's age \n" ); document.write( ". \n" ); document.write( "Y-2=4(S-2) \n" ); document.write( "Y-2=4S-8 \n" ); document.write( "Y=4S-6 Use this to substitute for Y below. \n" ); document.write( ". \n" ); document.write( "Y-8=10(S-8) \n" ); document.write( "Y-8=10S-80 \n" ); document.write( "Y=10S-72 Substitute for Y from above. \n" ); document.write( "4S-6=10S-72 Subtract 4S from each side. \n" ); document.write( "-6=6S-72 Add 72 to each side. \n" ); document.write( "66=6S \n" ); document.write( "11=S ANSWER: The son is currently 11 years old. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "Y-2=4(S-2) \n" ); document.write( "Y-2=4(11-2) \n" ); document.write( "Y-2=4(9) \n" ); document.write( "Y-2=36 \n" ); document.write( "Y=38 You are currently 38 years old \n" ); document.write( ". \n" ); document.write( "Y-8=10(S-8) \n" ); document.write( "38-8=10(11-8) \n" ); document.write( "30=10(3) \n" ); document.write( "30=30 \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |