document.write( "Question 972925: 2 years ago I was 4 times my sons age. 8 years ago I was 10 times his age.
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Algebra.Com's Answer #595176 by Boreal(15235)\"\" \"About 
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my age=x; son's age=y\r
\n" ); document.write( "\n" ); document.write( "11 years old ANSWER.\r
\n" ); document.write( "\n" ); document.write( "x-2=4*(y-2)
\n" ); document.write( "x-8=10*(y-8)\r
\n" ); document.write( "\n" ); document.write( "x=4y-8+2=4y-6
\n" ); document.write( "x=10y-80+8=10y-72\r
\n" ); document.write( "\n" ); document.write( "10y-72=4y-6
\n" ); document.write( "6y=66
\n" ); document.write( "y=11 son's age\r
\n" ); document.write( "\n" ); document.write( "two years earlier, son was 9, you were 36
\n" ); document.write( "you are 38 now.\r
\n" ); document.write( "\n" ); document.write( "eight years ago, you were 30, son was 3.\r
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