document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=972916>Question 972916</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help!<BR>\n" );
document.write( "I need to find an estimated volume for a field study I have just done and I'm not sure if I am doing it right.\r<BR>\n" );
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document.write( "I have a 500x500mm set square that is placed on the ground to measure the distribution of wrack (seaweed) within the square, I get an approximate covering of 40%. The depth of the wrack is measured and averages 4cm in depth. What is the volume in cm^3 within the square?<BR>\n" );
document.write( "After doing this 6 times, the average percentage covering was 12.5% and the average depth was 1.25cm, do you just use the same formula as the first part with the 40% & 4cm? If not, what is the volume in cm^3 for this one too? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #595157 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=595157\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i'm not exactly sure what you trying to do, but my impression is this.<BR>\n" );
document.write( "your area is 500 * 500 mm^2 which is equal to 250,000 mm^2.\r<BR>\n" );
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document.write( "40% of this area is covered with seaweed.\r<BR>\n" );
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document.write( "i would calculate that as .4 * 250,000 mm^2 = 100,000 mm^2 of the area is covered in seaweed.\r<BR>\n" );
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document.write( "you are told that the depth of the seaweed is an average of 4 cm.\r<BR>\n" );
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document.write( "since there are 10 mm for every cm, that means the average depth is 40 mm.\r<BR>\n" );
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document.write( "the volume of the seaweed would therefore be 100,000 * 40 = 4,000,000 mm^3.\r<BR>\n" );
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document.write( "if you are looking for the average depth of the seaweed over the whole 250,000 mm^2 area, then the formula would be:\r<BR>\n" );
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document.write( "250,000 * x = 4,000,000.\r<BR>\n" );
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document.write( "solve for x to get x = 4,000,000 / x = 16 mm which is equal to 1.6 cm.\r<BR>\n" );
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document.write( "the average depth of the seaweed over the whole 250,000 square mm is equal to 16 mm which is equal to 1.6 cm.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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