document.write( "Question 972798: log SQRT3 1/9=x \n" ); document.write( "
Algebra.Com's Answer #595127 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
log SQRT3 1/9=x
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\n" ); document.write( "\"log%28sqrt%283%29%2C1%2F9%29+=+x\"
\n" ); document.write( "\"log%283%5E%281%2F2%29%2C3%5E%28-2%29%29+=+x\"
\n" ); document.write( "x = -4
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\n" ); document.write( "If that's not obvious, email via the TY note.
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