document.write( "Question 972802: Find three consecutive numbers such that the sum of one-fourth the first and one-fifth the second is five less than one-seventh the third. \n" ); document.write( "

Algebra.Com's Answer #595109 by macston(5194) $\"\"$ $\"About$

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\n" ); document.write( "n, n+1, n+2= three consecutive numbers
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\n" ); document.write( " $\"%281%2F4%29n%2B%281%2F5%29%28n%2B1%29=%281%2F7%29%28n%2B2%29-5\"$
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\n" ); document.write( " $\"%2863%2F140%29n%2B%2828%2F140%29=%2820%2F140%29n-%28660%2F140%29\"$ Multiply by 140.
\n" ); document.write( " $\"63n%2B28=20n-660\"$ Subtract (20n+28) from each side.
\n" ); document.write( " $\"43n=-668\"$ Divide each side by 43.
\n" ); document.write( " $\"n=-16\"$ The first number is -16.
\n" ); document.write( " $\"n%2B1=-16%2B1=-15\"$ The second number is -15.
\n" ); document.write( " $\"n%2B2=-16%2B2=-14\"$ The third number is -14.
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\n" ); document.write( "CHECK:
\n" ); document.write( " $\"%281%2F4%29-16%2B%281%2F5%29-15=%281%2F7%29-14-5\"$
\n" ); document.write( " $\"-4-3=-2-5\"$
\n" ); document.write( " $\"-7=-7\"$ \r
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