document.write( "Question 82909: Mary left home at 12 noon and drove to visit her mom who lives 20 miles away. After she arrived she stayed for 2 hours. Afterwards, she drove to her friend Sue's house who lives 15 miles from her mom. She arrived at Sue's at 3:00pm. If her speed heading for Sue's was 5 mph faster than her speed going to her mom's, find her average speed on the way to Sue's \n" ); document.write( "
Algebra.Com's Answer #59509 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! The time spent driving plus the 2 hours at her mom's adds up to the \n" ); document.write( "elapsed time of 3 hours (noon to 3 PM). \n" ); document.write( "If s is the average speed to her mom's, then s+5 is the average speed \n" ); document.write( "from her mom's to Sue's \n" ); document.write( " \n" ); document.write( "This is just \n" ); document.write( " \n" ); document.write( "Multiply both sides by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Use the formula \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "therefore makes no sense) \n" ); document.write( " \n" ); document.write( "But the average speed going to Sue's is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "check answer \n" ); document.write( " \n" ); document.write( "Is this true when \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " |