document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=972857>Question 972857</A>: <I><SPAN STYLE=\"word-break: break-all;\"> f(x) = -9x2 + 2x + 4. I am having trouble finding an aproximate value for f(x)=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #595082 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=595082\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -9x^2 +2x +4 =0<BR>\n" );
document.write( "change all signs to make the square term positive.  It is much easier.\r<BR>\n" );
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document.write( "9x^2 - 2x - 4=0\r<BR>\n" );
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document.write( "quadratic formula\r<BR>\n" );
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document.write( "(1/18) [ 2 +/- sqrt (4+144)]    a=9 b=-2 4ac=4*(-4)*9\r<BR>\n" );
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document.write( "(1/18) 2+/- sqrt (148) ;;sqrt 148=12.17\r<BR>\n" );
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document.write( "(2+12.17)/18<BR>\n" );
document.write( "14.17/18=0.787\r<BR>\n" );
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document.write( "(2-12.17)/18<BR>\n" );
document.write( "-10.17/18= - 0.565\r<BR>\n" );
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document.write( "Approximate values are -0.565,+0.787\r<BR>\n" );
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