document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=972851>Question 972851</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The diagonal of the floor of a square room is 6 meters.\r<BR>\n" );
document.write( "\n" );
document.write( "What is the length of a side of the room? Round to the nearest tenth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #595068 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=595068\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> squares with side s have diagonals of s sqrt(2).  This is the Pythagorean theorem with angles 90-45-45.  it is sqrt(2)-1-1 ratio.\r<BR>\n" );
document.write( "\n" );
document.write( "Therefore, a diagonal of 6 has a side of 6/sqrt(2). Units are meters\r<BR>\n" );
document.write( "\n" );
document.write( "rationalizing by multiplying top and bottom by sqrt (2), 6 sqrt (2)/2\r<BR>\n" );
document.write( "\n" );
document.write( "That is 3 sqrt (2)=4.2 meters </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );