document.write( "Question 972828: the value of the sum in the 50th bracket of (1)+(2+3+4)+(5+6+7+8+9)+………………is \n" ); document.write( "
Algebra.Com's Answer #595057 by anand429(138)\"\" \"About 
You can put this solution on YOUR website!
No. of terms in each bracket follow sequence:
\n" ); document.write( "1,3,5,7..... (AP with common difference=2)
\n" ); document.write( "So no of terms in 50th bracket is the 50th term of the above sequence
\n" ); document.write( "i.e. N = 1+(50-1)*2
\n" ); document.write( " = 99
\n" ); document.write( "No starting term of 50th bracket can be found by counting the no. of terms already used in earlier brackets, since nos. are consecutive
\n" ); document.write( "Since we have the no. of terms in each bracket given by AP 1,3,5,7....
\n" ); document.write( "So no of terms in 49 brackets can be found by sum of 49 terms of above AP
\n" ); document.write( "So,
\n" ); document.write( "S(49) = \"%2849%2F2%29+%2A+%282%2A1+%2B+%2849-1%29%2A2%29\"
\n" ); document.write( " = \"2401\"
\n" ); document.write( "So 50th bracket starts with 2401, and contains 99 consecutive terms
\n" ); document.write( "So sum in the 50th bracket
\n" ); document.write( "= \"%2899%2F2%29+%2A+%282%2A2401+%2B+%2899-1%29%2A1%29\"
\n" ); document.write( "=\"242550\"
\n" ); document.write( "
\n" );